WebDuring a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. If this shot takes 3.33 × 10−2s , what is the distance over which the puck accelerates? Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution Want to see the full answer? WebSOLVING FOR DISPLACEMENT (Δ x) AND FINAL POSITION ( x) FROM AVERAGE VELOCITY WHEN ACCELERATION ( a) IS CONSTANT To get our first two new equations, we start with the definition of average velocity: . Substituting the simplified notation for and yields . Solving for yields , where the average velocity is .
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WebA hockey player makes a slap shot, exerting a constant force of 25.0 N on the puck for 0.16 seconds. What is the magnitude of the impulse given to the puck? impulse, Dp = FDt = 25.0 x 0.16 = 4.0 Ns. Problem 2 ... A 5.00 kg ball accelerates at a … WebDuring a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. If this shot takes 3.33 × 10 − 2 s, what is the distance over … WebThe equation ˉv = v0 + v 2 reflects the fact that, when acceleration is constant, v is just the simple average of the initial and final velocities. For example, if you steadily increase your velocity (that is, with constant acceleration) from 30 to 60 km/h, then your average velocity during this steady increase is 45 km/h. novant health shirts